Python Program to find the square root of a given number

Program

# Python Program to find the square root of a given number
inputNum = float(input('Enter a number: '))
squareRootOfNum = inputNum ** 0.5
print('The square root of %0.3f is %0.3f'%(inputNum ,squareRootOfNum))

This program calculates the square root of a user-provided number using exponentiation.

1. Take User Input

   • The program asks the user to enter a number (can be an integer or a decimal).

2. Calculate Square Root

   • The square root is found using the exponentiation operator ** 0.5.
   • In mathematics, the square root of x is the value y such that y * y = x.

3. Display Output

   • The result is printed with 3 decimal places using '%0.3f' % (inputNum, squareRootOfNum).

Key Takeaways

• The exponentiation operator ** 0.5 is a simple way to calculate the square root.
• The program supports floating-point numbers.
• The output is formatted to display three decimal places.

Output

$ python3 FindSquareRoot.py 
Enter a number: 529
The square root of 529.000 is 23.000